Verified Mathematical Model & Formulation
Horsepower (HP) = (Torque (lb-ft) × RPM) / 5,252 Kilowatts (kW) = (Torque (N·m) × RPM) / 9,549
Relates rotational mechanical work done over time to standard power units through angular velocity conversion constants (5,252 for imperial, 9,549 for metric).
Configurable Parameters & Standard Units
- Rotational Speed (RPM): (Default: 1750 count)
- Torque (lb-ft): (Default: 30 lb_ft)
Standard Worked Example & Practical Verification
Scenario: A pump operates at 1,750 RPM requiring 45 lb-ft of torque.
Calculated Solution
15.0 Horsepower (11.2 kW)
Practical Takeaway: Specify a standard 15 HP 1,800 synchronous RPM industrial induction motor.
Frequently Asked Questions
Why is 5,252 the constant in the horsepower formula?
Because 1 HP equals 33,000 ft-lbs/min, and one full revolution covers 2π radians. 33,000 ÷ (2 × π) = 5,252.11.